Open file Command to Distinguish between (x86 or x64) OS

[Larva King]

What would the syntax be for an open file command to only open that file if it is a (x86 or x64) OS.

[Desolator]

Here you are:

if System.Is64BitOS() == true then 
	--[[
		you can use File.Run, too, but if you don't need to get the return code
		use Shell.Execute as File.Run can fail on Vista because of UAC
	--]]
	Shell.Execute( "AutoPlay\\Docs\\x64.exe", "open", "", "", SW_SHOWNORMAL); 
else 
	Shell.Execute( "AutoPlay\\Docs\\x86.exe", "open", "", "", SW_SHOWNORMAL); 
end

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