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View Full Version : cannot get expression accept path %appdir%\openlog.ver


Sooty
10-18-2004, 08:22 AM
i have simple that search for file that

1. Search for file openlog.ver at %appdir%\install
2. IF Found "%FileSearchResult%"=%appdir%install\openlog.ver
3. Show dialog "Found Openlog.ver at %FileSearchResult%

The problem is that i cannot understand how to use line 2 as when i create the expression, it throws up an error during creation "Invalid Escape Sequence"

and consequintly line 3 does not show up correctly
( i think i'm missing somthing relativly easy and simple and being a bit thick today)

Sooty
10-18-2004, 09:45 AM
Found the Soloution myself

Very Simple

Assign Variable %Openlog_ver%
Value %appdir%install\openlog.ver

then use %openlog_ver% in Expression

:lol