need help } if a window is detected then change something

[nad46]

alright the title isnt clear but

what i want is when a specific EXE is open then a label is changed

such as

label game.EXE : not opened

and once it detects as the EXE as open
then

game.EXE : open

[nad46]

im thinking may useing Window.EnumerateProcesses and the procsess game.EXE then label.settext to whatever

but im not sure can some 1 help me out:huh:huh

[123456789]

Hi
This is for 50% of your work!
I can not other 50% ! because i'm newbie
run this project and then
you run the "game.exe" and see result in lable

[screwed over]

function FindRunningEXE(exeName)
local eProc = Window.EnumerateProcesses(true);
for handle, ProcPath in eProc do
local spPath = String.SplitPath(ProcPath);
local lspPath = String.Lower(spPath.Filename..spPath.Extension);
local lexeName = String.Lower(exeName);
if lspPath == lexeName then
return handle
end
end
end

handle = FindRunningEXE("game.exe")
if handle ~= nil then
Label.SetText("Label1", handle);
else
Label.SetText("Label1", "Not open");
end

returns nil if the process isnt running, it returns the window handle otherwise.